-2z^2-(2-I)z+i=0

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Solution for -2z^2-(2-I)z+i=0 equation:


Simplifying
-2z2 + -1(2 + -1I) * z + i = 0

Reorder the terms for easier multiplication:
-2z2 + -1z(2 + -1I) + i = 0
-2z2 + (2 * -1z + -1I * -1z) + i = 0
-2z2 + (-2z + 1zI) + i = 0

Reorder the terms:
i + -2z + 1zI + -2z2 = 0

Solving
i + -2z + 1zI + -2z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2z' to each side of the equation.
i + -2z + 1zI + 2z + -2z2 = 0 + 2z

Reorder the terms:
i + -2z + 2z + 1zI + -2z2 = 0 + 2z

Combine like terms: -2z + 2z = 0
i + 0 + 1zI + -2z2 = 0 + 2z
i + 1zI + -2z2 = 0 + 2z
Remove the zero:
i + 1zI + -2z2 = 2z

Add '-1zI' to each side of the equation.
i + 1zI + -1zI + -2z2 = 2z + -1zI

Combine like terms: 1zI + -1zI = 0
i + 0 + -2z2 = 2z + -1zI
i + -2z2 = 2z + -1zI

Add '2z2' to each side of the equation.
i + -2z2 + 2z2 = 2z + -1zI + 2z2

Combine like terms: -2z2 + 2z2 = 0
i + 0 = 2z + -1zI + 2z2
i = 2z + -1zI + 2z2

Simplifying
i = 2z + -1zI + 2z2

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